Integrand size = 20, antiderivative size = 195 \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}-\frac {\left (b \left (15 b^2-52 a c\right )-2 c \left (5 b^2-12 a c\right ) x^3\right ) \sqrt {a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}+\frac {\left (5 b^2-4 a c\right ) \text {arctanh}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right )}{8 c^{7/2}} \]
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Time = 0.16 (sec) , antiderivative size = 195, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1371, 752, 846, 793, 635, 212} \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\frac {\left (5 b^2-4 a c\right ) \text {arctanh}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right )}{8 c^{7/2}}-\frac {\left (b \left (15 b^2-52 a c\right )-2 c x^3 \left (5 b^2-12 a c\right )\right ) \sqrt {a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}+\frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}} \]
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Rule 212
Rule 635
Rule 752
Rule 793
Rule 846
Rule 1371
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {x^4}{\left (a+b x+c x^2\right )^{3/2}} \, dx,x,x^3\right ) \\ & = \frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 \text {Subst}\left (\int \frac {x^2 (6 a+3 b x)}{\sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{3 \left (b^2-4 a c\right )} \\ & = \frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}-\frac {2 \text {Subst}\left (\int \frac {x \left (-6 a b-\frac {3}{2} \left (5 b^2-12 a c\right ) x\right )}{\sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{9 c \left (b^2-4 a c\right )} \\ & = \frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}-\frac {\left (b \left (15 b^2-52 a c\right )-2 c \left (5 b^2-12 a c\right ) x^3\right ) \sqrt {a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}+\frac {\left (5 b^2-4 a c\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{8 c^3} \\ & = \frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}-\frac {\left (b \left (15 b^2-52 a c\right )-2 c \left (5 b^2-12 a c\right ) x^3\right ) \sqrt {a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}+\frac {\left (5 b^2-4 a c\right ) \text {Subst}\left (\int \frac {1}{4 c-x^2} \, dx,x,\frac {b+2 c x^3}{\sqrt {a+b x^3+c x^6}}\right )}{4 c^3} \\ & = \frac {2 x^9 \left (2 a+b x^3\right )}{3 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}}-\frac {2 b x^6 \sqrt {a+b x^3+c x^6}}{3 c \left (b^2-4 a c\right )}-\frac {\left (b \left (15 b^2-52 a c\right )-2 c \left (5 b^2-12 a c\right ) x^3\right ) \sqrt {a+b x^3+c x^6}}{12 c^3 \left (b^2-4 a c\right )}+\frac {\left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right )}{8 c^{7/2}} \\ \end{align*}
Time = 0.65 (sec) , antiderivative size = 170, normalized size of antiderivative = 0.87 \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\frac {4 a^2 c \left (-13 b+6 c x^3\right )+b^2 x^3 \left (15 b^2+5 b c x^3-2 c^2 x^6\right )+a \left (15 b^3-62 b^2 c x^3-20 b c^2 x^6+8 c^3 x^9\right )}{12 c^3 \left (-b^2+4 a c\right ) \sqrt {a+b x^3+c x^6}}+\frac {\left (-5 b^2+4 a c\right ) \log \left (c^3 \left (b+2 c x^3-2 \sqrt {c} \sqrt {a+b x^3+c x^6}\right )\right )}{8 c^{7/2}} \]
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\[\int \frac {x^{14}}{\left (c \,x^{6}+b \,x^{3}+a \right )^{\frac {3}{2}}}d x\]
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none
Time = 0.31 (sec) , antiderivative size = 591, normalized size of antiderivative = 3.03 \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\left [-\frac {3 \, {\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{6} + 5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} + {\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{3}\right )} \sqrt {c} \log \left (-8 \, c^{2} x^{6} - 8 \, b c x^{3} - b^{2} + 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {c} - 4 \, a c\right ) - 4 \, {\left (2 \, {\left (b^{2} c^{3} - 4 \, a c^{4}\right )} x^{9} - 5 \, {\left (b^{3} c^{2} - 4 \, a b c^{3}\right )} x^{6} - 15 \, a b^{3} c + 52 \, a^{2} b c^{2} - {\left (15 \, b^{4} c - 62 \, a b^{2} c^{2} + 24 \, a^{2} c^{3}\right )} x^{3}\right )} \sqrt {c x^{6} + b x^{3} + a}}{48 \, {\left (a b^{2} c^{4} - 4 \, a^{2} c^{5} + {\left (b^{2} c^{5} - 4 \, a c^{6}\right )} x^{6} + {\left (b^{3} c^{4} - 4 \, a b c^{5}\right )} x^{3}\right )}}, -\frac {3 \, {\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{6} + 5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} + {\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{3}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {-c}}{2 \, {\left (c^{2} x^{6} + b c x^{3} + a c\right )}}\right ) - 2 \, {\left (2 \, {\left (b^{2} c^{3} - 4 \, a c^{4}\right )} x^{9} - 5 \, {\left (b^{3} c^{2} - 4 \, a b c^{3}\right )} x^{6} - 15 \, a b^{3} c + 52 \, a^{2} b c^{2} - {\left (15 \, b^{4} c - 62 \, a b^{2} c^{2} + 24 \, a^{2} c^{3}\right )} x^{3}\right )} \sqrt {c x^{6} + b x^{3} + a}}{24 \, {\left (a b^{2} c^{4} - 4 \, a^{2} c^{5} + {\left (b^{2} c^{5} - 4 \, a c^{6}\right )} x^{6} + {\left (b^{3} c^{4} - 4 \, a b c^{5}\right )} x^{3}\right )}}\right ] \]
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\[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int \frac {x^{14}}{\left (a + b x^{3} + c x^{6}\right )^{\frac {3}{2}}}\, dx \]
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Exception generated. \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int { \frac {x^{14}}{{\left (c x^{6} + b x^{3} + a\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {x^{14}}{\left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int \frac {x^{14}}{{\left (c\,x^6+b\,x^3+a\right )}^{3/2}} \,d x \]
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